Comments on: a petroleum company has two different sources of crude oil.? http://askalandman.com/a-petroleum-company-has-two-different-sources-of-crude-oil.htm Questions and Answers Sat, 11 Feb 2012 00:01:47 +0000 http://wordpress.org/?v=2.9.2 hourly 1 By: Yves From Canada http://askalandman.com/a-petroleum-company-has-two-different-sources-of-crude-oil.htm/comment-page-1#comment-8231 Yves From Canada Thu, 20 May 2010 07:41:35 +0000 http://askalandman.com/a-petroleum-company-has-two-different-sources-of-crude-oil.htm#comment-8231 x = quantity needed of 55% hydrocarbons y = quantity needed of 95% hydrocarbons Two unknown values need two equations. Total quantity : x + y = 40 x = 40 - y Concentration : 0.55x + 0.95y = 0.90*40 = 36 First equation into this one : 0.55(40 - y) + 0.95y = 36 22 - 0.55y + 0.95y = 36 0.95y - 0.55y = 36 - 22 0.40y = 14 y = 14 / 0.40 y = 35 Into first equation : x = 40 - y x = 40 - 35 x = 5 So the mix will be : 5 gallons of crude oil at 55% hydrocarbons 35 gallons of crude oil at 95% hydrocarbons PROOF : 0.55(5) + 0.95(35) = 36 2.75 + 33.25 = 36 36 = 36 :ok x = quantity needed of 55% hydrocarbons
y = quantity needed of 95% hydrocarbons

Two unknown values need two equations.

Total quantity :
x + y = 40
x = 40 – y

Concentration :
0.55x + 0.95y = 0.90*40 = 36

First equation into this one :
0.55(40 – y) + 0.95y = 36
22 – 0.55y + 0.95y = 36
0.95y – 0.55y = 36 – 22
0.40y = 14
y = 14 / 0.40
y = 35

Into first equation :
x = 40 – y
x = 40 – 35
x = 5

So the mix will be :
5 gallons of crude oil at 55% hydrocarbons
35 gallons of crude oil at 95% hydrocarbons

PROOF :
0.55(5) + 0.95(35) = 36
2.75 + 33.25 = 36
36 = 36 :o k

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